TS EAMCET · Maths · Circle
If \(P_1, P_2, P_3\) are the perimeters of the three circles \(x^2+y^2+8 x-6 y=0\), \(4 x^2+4 y^2-4 x-12 y-186=0\) and \(x^2+y^2-6 x+6 y-9=0\) respectively, then
- A \(P_1 < P_2 < P_3\)
- B \(P_1 < P_3 < P_2\)
- C \(P_3 < P_2 < P_1\)
- D \(P_2 < P_3 < P_1\)
Answer & Solution
Correct Answer
(B) \(P_1 < P_3 < P_2\)
Step-by-step Solution
Detailed explanation
Given circle are \(x^2+y^2+8 x-6 y=0\) \[ \begin{gathered} 4 x^2+4 y^2-4 x-12 y-186=0 \text { and } \\ x^2+y^2-6 x+6 y-9=0 . \end{gathered} \] Let \(r_1, r_2\) and \(r_3\) be the radius of the respective circle, then…
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