TS EAMCET · Maths · Probability
If \(A\) and \(B\) are two independent events such that \(P(B)=\frac{2}{7}, P\left(A \cup B^c\right)=0.8\), then \(P(A)\) is equal to :
- A 0.1
- B 0.2
- C 0.3
- D 0.4
Answer & Solution
Correct Answer
(C) 0.3
Step-by-step Solution
Detailed explanation
\(\because P(B)=\frac{2}{7}\) and \(P\left(A \cup B^c\right)=0.8\) \(P\left(B^c\right)=1-\frac{2}{7}=\frac{5}{7}\) We know that \(P\left(A \cup B^c\right)=P(A)+P\left(B^c\right)-P(A) \cdot P\left(B^c\right)\) \(\Rightarrow \quad 0.8=P(A)+\frac{5}{7}-\frac{5}{7} P(A)\)…
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