TS EAMCET · Maths · Application of Derivatives
The value of \(c\) in the Lagrange's mean value theorem for \(f(x)=\sqrt{x-2}\) in the interval \([2,6]\) is
- A \(\frac{9}{2}\)
- B \(\frac{5}{2}\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(C) \(3\)
Step-by-step Solution
Detailed explanation
Given, \(f(x)=\sqrt{x-2}, x \in[2,6]\) We know that, by Lagrange's mean value theorem, their exist \(c \in(2,6)\) such that…
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