TS EAMCET · Maths · Pair of Lines
If \(\theta\) is the acute angle between the pair of lines \(\mathrm{H} \equiv a x^2-x y+b y^2=0, \tan \theta=5\) and \((1,-1)\) is a point on \(\mathrm{H}=0\) then \(a^2+a b+b^2=\)
- A 5
- B 14
- C 7
- D 13
Answer & Solution
Correct Answer
(C) 7
Step-by-step Solution
Detailed explanation
having a point \((1,-1)\) satisfy \( \Rightarrow {a}+{b}=-1 \) We know that pair of straight lines passing through origin is \(a x^2+2 h x y+b y^2=0\) On comparing (i) and (ii)…
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