TS EAMCET · Maths · Circle
The radical centre of the circles \(x^2+y^2=1, x^2+y^2-2 x-3=0\) and \(x^2+y^2-2 y-3=0\) is
- A \((1,1)\)
- B \((1,-1)\)
- C \((-1,1)\)
- D \((-1,-1)\)
Answer & Solution
Correct Answer
(D) \((-1,-1)\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} C_1=x^2+y^2-1 & =0 \\ C_2=x^2+y^2-2 x-3 & =0 \\ C_3=x^2+y^2-2 y-3 & =0 \end{aligned} \] On solving Eqs. (i) and (ii), we get \[ \begin{aligned} 2 x+2 & =0 \\ x & =-1 \end{aligned} \] \[ \Rightarrow \quad x=-1 \] On solving Eqs. (i) and (iii), we get…
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