TS EAMCET · Maths · Functions
The range of the function \(f(x)=-\sqrt{-x^2-6 x-5}\) is
- A \([0,2]\)
- B \([-2,0]\)
- C \([-2,2]\)
- D \((-\infty, 2]\)
Answer & Solution
Correct Answer
(B) \([-2,0]\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & -x^2-6 x-5 \\ D= & 36-4(-1)(-5)=16\end{aligned}\) \(\begin{array}{ll}\therefore \quad & -x^2-6 x-5 \in(-\infty, 4] \\ \text { for } & \sqrt{-x^2-6 x-5} \\ & f(x) \in[0,2] \\ & -f(x) \in[-2,0]\end{array}\)
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