TS EAMCET · Maths · Functions
If \(f: R \rightarrow R\) is defined by \(f(x)=x-[x]-\frac{1}{2}\) for \(x \in R\), where \([x]\) is the greatest integer not exceeding \(x\), then \(\left\{x \in R: f(x)=\frac{1}{2}\right\}\) is equal to :
- A \(Z\), the set of all integers
- B \(N\), the set of all natural numbers
- C \(\phi\), the empty set
- D R
Answer & Solution
Correct Answer
(C) \(\phi\), the empty set
Step-by-step Solution
Detailed explanation
\(\because \quad f(x)=x-[x]-\frac{1}{2}\) Also \(\quad f(x)=\frac{1}{2}\) \(\therefore \quad \frac{1}{2}=x-[x]-\frac{1}{2}\) \(\Rightarrow \quad x-[x]=1\) \(\Rightarrow \quad\{x\}=1\) \([\because x=[x]+\{x\}]\) Which is not possible.…
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