ExamBro
ExamBro
TS EAMCET · Maths · Binomial Theorem

The term independent of \(x(x>0, x \neq 1)\) in the expansion of \(\left[\frac{(x+1)}{\left(x^{2 / 3}-x^{1 / 3}+1\right)}-\frac{(x-1)}{(x-\sqrt{x})}\right]^{10}\)

  1. A \(105\)
  2. B \(210\)
  3. C \(315\)
  4. D \(420\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(210\)

Step-by-step Solution

Detailed explanation

\begin{aligned} & {\left[\frac{(x+1)}{\left(x^{2 / 3}-x^{1 / 3}+1\right)}-\frac{(x-1)}{(x-\sqrt{x})}\right]^{10}} \\ & \quad=\left[\frac{\left(x^{1 / 3}\right)^3+1^3}{\left(x^{2 / 3}-x^{1 / 3}+1\right)}-\frac{\left\{(\sqrt{x})^2-1\right\}}{\sqrt{x}(\sqrt{x}-1)}\right]^{10} \\ &…