TS EAMCET · Maths · Matrices
If \(\mathrm{A}=\left[\begin{array}{ccc}k & 5 & 2 \\ 2 & -k & 5 \\ 5 & 2 & -k\end{array}\right]\) and \(\operatorname{det} A=190\) then \(\operatorname{Adj} A=\)
- A \(\left[\begin{array}{ccc}-1 & 19 & 31 \\ 31 & -19 & -11 \\ 19 & 19 & -19\end{array}\right]\)
- B \(\left[\begin{array}{ccc}-1 & 31 & 19 \\ 19 & -19 & 19 \\ 31 & -11 & -19\end{array}\right]\)
- C \(\left[\begin{array}{ccc}-1 & 19 & 31 \\ -31 & -19 & -11 \\ 19 & 19 & -19\end{array}\right]\)
- D \(\left[\begin{array}{ccc}-1 & -31 & 19 \\ 19 & -19 & 19 \\ 31 & -11 & -19\end{array}\right]\)
Answer & Solution
Correct Answer
(A) \(\left[\begin{array}{ccc}-1 & 19 & 31 \\ 31 & -19 & -11 \\ 19 & 19 & -19\end{array}\right]\)
Step-by-step Solution
Detailed explanation
\(A=\left[\begin{array}{ccc}K & 5 & 2 \\ 2 & -K & 5 \\ 5 & 2 & -K\end{array}\right]\)…
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