TS EAMCET · Maths · Differential Equations
The solution of \(\cos y+(x \sin y-1) \frac{d y}{d x}=0\) is
- A \(x \sec y=\tan y+C\)
- B \(\tan y-\sec y=C x\)
- C \(\tan y+\sec y=C x\)
- D \(x \sec y+\tan y=C\)
Answer & Solution
Correct Answer
(A) \(x \sec y=\tan y+C\)
Step-by-step Solution
Detailed explanation
Given differential equation can be rewritten as \[ \begin{aligned} & \cos y \frac{d y}{d x}+x \sin y-1=0 \\ & \Rightarrow \quad \frac{d x}{d y}+(\tan y) x=\sec y \\ & \end{aligned} \] It is a linear differential equation of the form…
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