TS EAMCET · Maths · Circle
The inverse of the point \((1,2)\) with respect to the circle \(x^2+y^2-4 x-6 y+9=0\), is
- A \(\left(1, \frac{1}{2}\right)\)
- B \((2,1)\)
- C \((0,1)\)
- D \((1,0)\)
Answer & Solution
Correct Answer
(C) \((0,1)\)
Step-by-step Solution
Detailed explanation
The equation of pole w.r.t. the point \((1,2)\) to the circle \(x^2+y^2-4 x-6 y+9=0\) is \[ \Rightarrow \quad \begin{aligned} x+2 y-2(x+1)-3(y+2)+9 & =0 \\ \Rightarrow \quad x+y-1 & =0 \end{aligned} \] \(\Rightarrow \quad x+y-1=0\) foot \((\alpha, \beta)\) of the perpendicular…
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