TS EAMCET · Maths · Quadratic Equation
The product of all the real roots of \(x^2-8 x+9-\frac{8}{x}+\frac{1}{x^2}=0\) is
- A 2
- B 1
- C 3
- D 7
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
We have, \[ \begin{aligned} x^2-8 x+9-\frac{8}{x}+\frac{1}{x^2} & =0 \\ \Rightarrow \quad x^4-8 x^3+9 x^2-8 x+1 & =0 \end{aligned} \] Product of roots \(=1\)
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