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TS EAMCET · Maths · Complex Number

If 1,ω,ω2 are the cube roots of unity, n and n>2 then the least value of n such that 1+ω is a root of xn-x=0 is

  1. A 3
  2. B 5
  3. C 7
  4. D 4
Verified Solution

Answer & Solution

Correct Answer

(C) 7

Step-by-step Solution

Detailed explanation

It is given that 1+ω is the root of xn-x=0 1+ωn-1+ω=0 ⇒-ω2n-1+ω=0 ∵1+ω+ω2=0 ⇒ -1nω2n-1-ω=0      ⋯1 Since, ω is the cube root at unity, So 1+ω+ω2=0, hence for 1…
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