TS EAMCET · Maths · Probability
A random variable \(\mathrm{X}\) has the following distribution. \begin{array}{|c|c|c|c|c|c|c|} \hline \boldsymbol{X}=\boldsymbol{x}_{\boldsymbol{i}} & -2 & -1 & 0 & 1 & 2 & 3 \ \hline \boldsymbol{P}\left(\boldsymbol{X}=\boldsymbol{x}_{\boldsymbol{i}}\right) & 0.1 & \mathrm{k} & 0.2 & 2 \mathrm{k} & 3 \mathrm{k} & \mathrm{k} \ \hline \end{array} Then the variance of this distribution is
- A 2.64
- B 2.8
- C 2.16
- D 1.86
Answer & Solution
Correct Answer
(C) 2.16
Step-by-step Solution
Detailed explanation
\begin{array}{|c|c|c|c|c|} \hline \boldsymbol{x} & \mathbf{P}(\boldsymbol{x}) & \boldsymbol{x}^2 & \boldsymbol{x}^2 \cdot \mathbf{P}(\boldsymbol{x}) & \boldsymbol{x} \cdot \mathbf{P}(\boldsymbol{x}) \\ \hline-2 & 0.1 & 4 & 0.4 & -0.2 \\ -1 & \mathrm{~K} & 1 & \mathrm{~K} &…
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