TS EAMCET · Maths · Pair of Lines
The equation of the pair of straight lines through the point \((1,1)\) and perpendicular to the pair of straight lines \(3 x^2-8 x y+5 y^2=0\) is
- A \(5 x^2+8 x y+3 y^2-14 x-18 y+16=0\)
- B \(5 x^2+8 x y+3 y^2-18 x-14 y+16=0\)
- C \(5 x^2-8 x y+3 y^2-18 x-14 y+32=0\)
- D \(5 x^2-8 x y+3 y^2-14 x-18 y+32=0\)
Answer & Solution
Correct Answer
(B) \(5 x^2+8 x y+3 y^2-18 x-14 y+16=0\)
Step-by-step Solution
Detailed explanation
We know that, the equations of the line passing through the origin and perpendicular to the lines given by \(3 x^2-8 x y+5 y^2=0\) is \(5 x^2+8 x y+3 y^2=0\) Now, shifting the origin at \((1,1)\) the equations of the required lines are…
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