TS EAMCET · Maths · Determinants
All the real values of \(p, q\) so that the system of equations
\(\begin{array}{r}
2 x+p y+6 z=8 \\
x+2 y+q z=5 \\
x+y+3 z=4
\end{array}\)
may have no solution are
- A \(p=2, q \neq 3\)
- B \(p=2, q=\frac{15}{2}\)
- C \(p \neq 2, q=3\)
- D \(p=3, q=\frac{15}{4}\)
Answer & Solution
Correct Answer
(C) \(p \neq 2, q=3\)
Step-by-step Solution
Detailed explanation
We have, \(\begin{array}{r} 2 x+p y+6 z=8 \\ x+2 y+q z=5 \\ x+y+3 z=4 \end{array}\) Now, if we express above equation in matrix form, We have, \(A X=B\) Where,…
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