TS EAMCET · Maths · Probability
Two persons A and B play a game by throwing two dice. If the sum of the numbers appeared on the two dice is even, A will get \(\frac{1}{2}\) point and B will get \(\frac{1}{2}\) point. If the sum is odd, A will get one point and B will get no point. The arithmetic mean of the random variable of the number of points of A is
- A \(\frac{1}{2}\)
- B \(\frac{1}{4}\)
- C \(1\)
- D \(\frac{3}{4}\)
Answer & Solution
Correct Answer
(D) \(\frac{3}{4}\)
Step-by-step Solution
Detailed explanation
\(P(\text{even sum}) = \frac{18}{36} = \frac{1}{2}\) \(P(\text{odd sum}) = \frac{18}{36} = \frac{1}{2}\) \(E[A] = (\frac{1}{2})P(\text{even sum}) + (1)P(\text{odd sum})\) \(E[A] = (\frac{1}{2})(\frac{1}{2}) + (1)(\frac{1}{2})\) \(E[A] = \frac{1}{4} + \frac{1}{2}\)…
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