TS EAMCET · Maths · Parabola
The focal distance of a point \((5,5)\) on the parabola \(x^2-2 x-4 y+5=0\) is
- A \(5\)
- B \(8\)
- C \(10\)
- D \(12\)
Answer & Solution
Correct Answer
(A) \(5\)
Step-by-step Solution
Detailed explanation
\((x-1)^2=4(y-1)\) \(a=1\) Directrix: \(y=1-1=0\) Focal distance: \(|5-0|=5\)
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