TS EAMCET · Maths · Pair of Lines
The product of the perpendicular distances from the origin on the pair of straight lines \(12 x^2+25 x y+12 y^2+10 x+11 y+2=0\), is
- A \(\frac{1}{25}\)
- B \(\frac{2}{25}\)
- C \(\frac{3}{25}\)
- D \(\frac{4}{25}\)
Answer & Solution
Correct Answer
(B) \(\frac{2}{25}\)
Step-by-step Solution
Detailed explanation
Given that \(12 x^2+25 x y+12 y^2+10 x+11 y+2=0\) ...(i) First we take homogeneous part of Eq. (i), \(\begin{aligned} & \text { i.e. } 12 x^2+25 x y+12 y^2=0 \\ & \Rightarrow(3 x+4 y)(4 x+3 y)=0 \end{aligned}\) So, let the lines represented by Eq. (i) be \(3 x+4 y+c_1=0\)…
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