TS EAMCET · Maths · Trigonometric Ratios & Identities
If \(\alpha+\beta+\gamma=2 \theta\), then \(\cos \theta+\cos (\theta-\alpha)\) \(+\cos (\theta-\beta)+\cos (\theta-\gamma)\) is equal to
- A \(4 \sin \frac{\alpha}{2} \cdot \cos \frac{\beta}{2} \cdot \sin \frac{\gamma}{2}\)
- B \(4 \cos \frac{\alpha}{2} \cdot \cos \frac{\beta}{2} \cdot \cos \frac{\gamma}{2}\)
- C \(4 \sin \frac{\alpha}{2} \cdot \sin \frac{\beta}{2} \cdot \sin \frac{\gamma}{2}\)
- D \(4 \sin \alpha \cdot \sin \beta \cdot \sin \gamma\)
Answer & Solution
Correct Answer
(B) \(4 \cos \frac{\alpha}{2} \cdot \cos \frac{\beta}{2} \cdot \cos \frac{\gamma}{2}\)
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