TS EAMCET · Maths · Differentiation
If \(a x^2+2 h x y+b y^2=3\), then \(\frac{d^2 y}{d x^2}=\)
- A \(\frac{\left(h x^2+b y+a x\right)}{(a x+h y)^2}\)
- B \(\frac{\left(a x y+h x^2+b y x\right)}{(a x+b y)^2}\)
- C \(\frac{3\left(h^2-a b\right)}{(h x+b y)^3}\)
- D \(\frac{(a b+h)^2}{(a x+h y)^2}\left[h\left(x^2+y^2\right)+x y(a+b)\right]\)
Answer & Solution
Correct Answer
(C) \(\frac{3\left(h^2-a b\right)}{(h x+b y)^3}\)
Step-by-step Solution
Detailed explanation
We have, \[ a x^2+2 h x y+b y^2=3 \] On differentiating with respect to \(x\), we get \[ \begin{aligned} & 2 a x+2 h x \frac{d y}{d x}+2 h y+2 b y \frac{d y}{d x}=0 \\ & \frac{d y}{d x}=-\frac{(a x+h y)}{(b y+h x)} \end{aligned} \] Again differentiating with respect to \(x\), we…
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