TS EAMCET · Maths · Continuity and Differentiability
If \(f: R \rightarrow R\) is defined as \(f(x)=|x+1|+|x-1|\), then \(f(x)\) is
- A not differentiable at every real number
- B not differentiable at - 1and 1 only
- C not differentiable at - 1, 0 and 1
- D differentiable on R
Answer & Solution
Correct Answer
(B) not differentiable at - 1and 1 only
Step-by-step Solution
Detailed explanation
Given, \(f(x)=|x+1|+|x-1|\) \(f(x)\) has a corner point only at \(x=1,-1\) by the graph. So, \(f(x)\) is not differentiable at \(x=-1,1\) only.
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