TS EAMCET · Maths · Quadratic Equation
The product of real of the equation \(|x|^{6 / 5}-26|x|^{3 / 5}-27=0\)
- A \(-3^{10}\)
- B \(-3^{12}\)
- C \(-3^{12 / 5}\)
- D \(-3^{21 / 5}\)
Answer & Solution
Correct Answer
(A) \(-3^{10}\)
Step-by-step Solution
Detailed explanation
Given equation is \(|x|^{6 / 5}-26|x|^{3 / 5}-27=0\) Put \(|x|^{3 / 5}=t\)…
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