TS EAMCET · Maths · Trigonometric Equations
If \(0 < \theta < \frac{\pi}{2}\), then solution of the equation \(\sin \theta-3 \sin 2 \theta+\sin 3 \theta=\cos \theta-3 \cos 2 \theta+\cos 3 \theta\) is
- A \(\frac{\pi}{16}\)
- B \(\frac{\pi}{12}\)
- C \(\frac{\pi}{8}\)
- D \(\frac{\pi}{6}\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{8}\)
Step-by-step Solution
Detailed explanation
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