TS EAMCET · Maths · Indefinite Integration
\(\int \frac{d x}{\left(x^2+1\right)\left(x^2+4\right)}=\)
- A \(\frac{1}{3} \tan ^{-1} x+\frac{1}{6} \tan ^{-1}\left(\frac{x}{2}\right)+c\)
- B \(\frac{1}{3} \tan ^{-1} x-\frac{1}{3} \tan ^{-1}\left(\frac{x}{2}\right)+c\)
- C \(\frac{1}{3} \tan ^{-1} x+\frac{1}{3} \tan ^{-1}\left(\frac{x}{2}\right)+c\)
- D \(\frac{1}{3} \tan ^{-1} x-\frac{1}{6} \tan ^{-1}\left(\frac{x}{2}\right)+c\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{3} \tan ^{-1} x-\frac{1}{6} \tan ^{-1}\left(\frac{x}{2}\right)+c\)
Step-by-step Solution
Detailed explanation
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