TS EAMCET · Maths · Circle
If \((3,1)\) and \((-2,4)\) are points on a circle \(S\) whose centre lies on the line \(x-y+1=0\) then the parametric equations of S are
- A \(x=-1+\sqrt{17} \cos \theta, y=\sqrt{17} \sin \theta\)
- B \(x=2+\sqrt{13} \cos \theta, y=1+\sqrt{13} \sin \theta\)
- C \(x=\sqrt{26} \cos \theta, y=-1+\sqrt{26} \sin \theta\)
- D \(\mathrm{x}=-1+\sqrt{19} \cos \theta, \mathrm{y}=2+\sqrt{19} \sin \theta\)
Answer & Solution
Correct Answer
(A) \(x=-1+\sqrt{17} \cos \theta, y=\sqrt{17} \sin \theta\)
Step-by-step Solution
Detailed explanation
Centre lies on \(x-y+1=0\) \(\therefore \quad\) Centre: \(C(\alpha, \alpha+1)\) Let \(P(3,1)\) and \(Q(-2,4)\) are 2 points…
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