TS EAMCET · Maths · Circle
If \(\mathrm{A}, \mathrm{B}\) are the points of contact of the tangents drawn from the point \((-3,1)\) to the circle \(x^2+y^2-4 x+2 y-4=0\), then the equation of the circumcircle of the triangle PAB is
- A \(x^2+y^2-6 x+2 y-6=0\)
- B \(x^2+y^2-x+7=0\)
- C \(x^2+y^2+x-7=0\)
- D \(x^2+y^2+6 x-2 y-6=0\)
Answer & Solution
Correct Answer
(C) \(x^2+y^2+x-7=0\)
Step-by-step Solution
Detailed explanation
Given circle \(S: x^2+y^2-4x+2y-4=0\) Given point \(P(-3,1)\) Equation of chord of contact \(T: xx_1+yy_1+g(x+x_1)+f(y+y_1)+c=0\) From \(S\), \(g=-2, f=1, c=-4\) \(T: x(-3)+y(1)-2(x-3)+1(y+1)-4=0\) \(T: -3x+y-2x+6+y+1-4=0\) \(T: -5x+2y+3=0\) Equation of circumcircle of…
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