TS EAMCET · Maths · Circle
The point of contact of the circles \(x^2+y^2+2 x+2 y+1=0\) and \(\quad x^2+y^2-2 x+2 y+1=0\) is
- A (0, 1)
- B (0,-1)
- C (1, 0)
- D (-1, 0)
Answer & Solution
Correct Answer
(B) (0,-1)
Step-by-step Solution
Detailed explanation
Given equation of circles are \(\begin{aligned} S_1 & \equiv x^2+y^2+2 x+2 y+1=0 \\ \text { and } \quad S_2 \equiv x^2+y^2-2 x+2 y+1 & =0 \end{aligned}\) In circle \(S_1\), centre \(c_1=(-1,-1)\), radius \(r_1=\sqrt{1+1-1}=1\) In circle \(S_2\), centre \(C_2=(1,-1)\), radius…
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