TS EAMCET · Chemistry · Surface Chemistry
10 mL of 0.5 M NaCl is required to coagulate 1 L of \(\mathrm{Sb}_2 \mathrm{~S}_3\) sol in 2 hours time. The flocculating value of NaCl (in milli moles) is
- A 20
- B 10
- C 5
- D 15
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
(Number of mole of NaCl required \(=\frac{10}{1000} \times 0.5\) \(=0.005 \mathrm{~mol}\) No. of milimoles, of \(\mathrm{NaCl}=0.005 \times 1000=5\) milimoles Floculating value is the minimum amount of NaCl in milimoles, required just to coagulate colloid.
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