TS EAMCET · Maths · Quadratic Equation
If \(\mathbb{R}-(\alpha, \beta)\) is the range of \(\frac{x+3}{(x-1)(x+2)}\), then the sum of the intercepts of the line \(\alpha x+\beta y+1=0\) on the coordinate axes is
- A \(-8\)
- B \(10\)
- C \(8\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
\(y=\frac{(x+3)}{(x-1)(x+2)}\)…
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