TS EAMCET · Maths · Vector Algebra
The orthogonal projection of \(\mathbf{a}\) on \(\mathbf{b}\) is
- A \(\frac{(\mathbf{a} \cdot \mathbf{b}) \mathbf{a}}{|\mathbf{a}|^2}\)
- B \(\frac{(\mathbf{a} \cdot \mathbf{b}) \mathbf{b}}{|\mathbf{b}|^2}\)
- C \(\frac{\mathbf{a}}{|\mathbf{a}|^2}\)
- D \(\frac{\mathbf{b}}{|\mathbf{b}|}\)
Answer & Solution
Correct Answer
(B) \(\frac{(\mathbf{a} \cdot \mathbf{b}) \mathbf{b}}{|\mathbf{b}|^2}\)
Step-by-step Solution
Detailed explanation
The orthogonal projection of \(\mathbf{a}\) on \(\mathbf{b}\) \(=\frac{(\mathbf{a} \cdot \mathbf{b}) \mathrm{b}}{|\mathrm{b}|^2}\)
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