TS EAMCET · Maths · Pair of Lines
The line \(x+2 y=k\) meets the curve \(2 x^2-2 x y+3 y^2+\) \(2 x-y-1=0\) at two points \(\mathrm{A}\) and \(\mathrm{B}\). Let \(\mathrm{O}\) be the origin. If the line segments \(\mathrm{OA}\) and \(\mathrm{OB}\) are perpendicular to each other, then \(k=\)
- A \(\pm 1\)
- B \(\pm 2\)
- C \(\pm 3\)
- D 4
Answer & Solution
Correct Answer
(A) \(\pm 1\)
Step-by-step Solution
Detailed explanation
Given line \(x+2 y=k\) meets the curve \(2 x^2-2 x y+\) \(3 y^2+2 x-y-1=0\) Take, \(\frac{x+2 y}{k}=1\) ...(i) From curve \(2 x^2-2 x y+3 y^2+2 x-y-1=0\)…
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