TS EAMCET · Chemistry · Electrochemistry
Given \(\mathrm{E}^{\circ} \mathrm{Mn}^{7+} / \mathrm{Mn}^{2+}=1.51 \mathrm{~V}, \mathrm{E}_{\mathrm{Mn}^{\circ+} / \mathrm{Mn}^{2+}}=1.23 \mathrm{~V}\) Calculate \(\mathrm{E}^{\circ} \mathrm{Mn}^{7+} / \mathrm{Mn}^{4+}\)
- A \(0.28 \mathrm{~V}\)
- B \(-0.28 \mathrm{~V}\)
- C \(1.7 \mathrm{~V}\)
- D \(0.48 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(1.7 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
\[ \begin{aligned} & \mathrm{E}_1^{\circ}=1.51 \mathrm{~V}, \quad \mathrm{E}_3^{\circ}=1.23 \mathrm{~V} \\ & \Delta \mathrm{G}_1^{\circ}=\Delta \mathrm{G}_2^{\circ}+\Delta \mathrm{G}_3^{\circ} \end{aligned} \] or,…
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