TS EAMCET · Maths · Permutation Combination
The number of ways in which 6 men and 4 women can be seated around a table so that a particular man and a particular woman never sit adjacent to each other is
- A 9 !
- B \(7 \times 8\) !
- C \(8 \times 8\) !
- D \(6 \times 7\) !
Answer & Solution
Correct Answer
(B) \(7 \times 8\) !
Step-by-step Solution
Detailed explanation
6 men and 4 women Excluding 1 particular man \& 1 women Place rest 8 people in around table by 7 ! ways Now 8 gaps are created Select 2 gaps by \({ }^8 \mathrm{C}_2\) ways \(\&\) arrange them in 2 ! ways Total ways \(=7 ! \times 8 \mathrm{C}_2 \cdot 2 !\)…
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