TS EAMCET · Maths · Heights and Distances
A person observes the top of a tower from a point \(A\) on the ground. The elevation of the tower from this point is \(60^{\circ}\). He moves \(60 \mathrm{~m}\) in the direction perpendicular to the line joining \(A\) and base of the tower. The angle of elevation of the tower from this point is \(45^{\circ}\). Then, the height of the tower (in metres) is
- A \(60 \sqrt{\frac{3}{2}}\)
- B \(60 \sqrt{2}\)
- C \(60 \sqrt{3}\)
- D \(60 \sqrt{\frac{2}{3}}\)
Answer & Solution
Correct Answer
(A) \(60 \sqrt{\frac{3}{2}}\)
Step-by-step Solution
Detailed explanation
In \(\triangle A B D\) \(\Rightarrow h=x \sqrt{3}\) In \(\triangle B A C\) \(\begin{aligned} B C^2 & =A B^2+A C^2 \\ \Rightarrow B C & =\sqrt{x^2+(60)^2} \\ & =\sqrt{x^2+3600} \end{aligned}\) \(\text {In } \triangle C B D, \tan 45^{\circ}=\frac{h}{\sqrt{3600+x^2}}\)…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- \(\mathbf{a}=4 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}\) and \(\mathbf{b}\) are two vectors in \(X O Y\) plane and \(\mathbf{a}\) is perpendicular to \(\mathbf{b}\). A vector \(\mathbf{c}\) lying in the same plane and having projections 1 and 2 respectively \(\mathbf{a}\) and \(\mathbf{b}\) isTS EAMCET 2019 Easy
- If the determinant of the matrix is zero for all thenTS EAMCET 2019 Easy
- The general solution of the equation \(\sqrt{6-5 \cos x+7 \sin ^2 x}-\cos x=0\) also satisfies the equationTS EAMCET 2025 Medium
- \(p\) is non-zero real number. If the equation whose roots are the squares of the roots of the equation \(x^3-p x^2+p x-1=0\) is identical with the given equation, then \(p=\)TS EAMCET 2020 Easy
- If \(y=\log \left(x-\sqrt{x^2-1}\right)\), then \(\left(x^2-1\right) y^{\prime \prime}+x y^{\prime}+e^y+\sqrt{x^2-1}=\)TS EAMCET 2024 Easy
- If \(\int \frac{x^2\left(x \sec ^2+\tan x\right)}{(x \tan x+1)^2} d x=\frac{-x^2}{x \tan x+1}+f(x)+c\), then \(f(\mathrm{x})=\)TS EAMCET 2023 Hard
More PYQs from TS EAMCET
- If \(A\) is a non-zero square matrix of order \(n\) with \(\operatorname{det}(I+A) \neq 0\) and \(A^3=O\), where \(I, O\) are unit and null matrices of order \(n \times n\) respectively, then \((I+A)^{-1}\) is equal toTS EAMCET 2010 Hard
- Let \(C\) be a curve \(a x^2+2 h x y+b y^2+2 g x+2 f y+c=0\) in \(a\) cartesian plane. By rotating the coordinate axes through an angle \(\frac{\pi}{4}\) in the positive direction, if the transformed equation of \(C\) is \(Y^2+X Y-X=0\), then \(\left(h^2-a b\right)-2 g f=\)TS EAMCET 2020 Medium
- Which of the following does not follow first law of thermodynamics? work heat change in internal energyTS EAMCET 2019 Easy
- The major product formed in the following reaction sequence is
\(CH _3 CH = CH _2 \xrightarrow[\substack{\text { iii } CH _3 CH _2 CHO \\ \text { iv } CrO _3}]{\substack{\text { i } HBr , \text { peroxide } \\ \text { ii } Mg }}\)TS EAMCET 2022 Hard - An electromagnetic wave is propagating in vacuum along direction. The magnetic field of the wave is given by . The electric field of this wave is ( speed of light)TS EAMCET 2022 Medium
- The objective and eyepiece of an astronomical telescope are double convex lenses with refractive index 1.5. When the telescope is adjusted to infinity, the separation between the two lenses is \(16 \mathrm{~cm}\). If the space between the lenses is now filled with water and again telescope is adjusted for infinity, then the present separation between the lenses isTS EAMCET 2012 Medium