TS EAMCET · Physics · Magnetic Effects of Current
A long straight wire carrying current \(16 \mathrm{~A}\) is bent at \(90^{\circ}\) such that half of the wire lies along the positive \(x\)-axis and other half lies along the positive \(y\)-axis. What is the magnitude of the magnetic field at the point, \(\mathbf{r}=(-2 \hat{\mathbf{i}}+0 \hat{\mathbf{j}}) \mathrm{mm}\) ? (Assume, \(\frac{\mu_0}{4 \pi}=10^{-7} \mathrm{H} \mathrm{m}^{-1}\) )
- A \(1.2 \mathrm{mT}\)
- B \(0.8 \mathrm{mT}\)
- C \(3.2 \mathrm{mT}\)
- D \(1.6 \mathrm{mT}\)
Answer & Solution
Correct Answer
(B) \(0.8 \mathrm{mT}\)
Step-by-step Solution
Detailed explanation
According to the question, a long straight wire is bent at \(90^{\circ}\) as shown in the figure, Where, current flowing through the wire, \(I=16 \mathrm{~A}\) \( \mathbf{r}=\mathrm{OP}=(-2 \hat{\mathbf{i}}+0 \hat{\mathbf{j}}) \mathrm{mm} \) Magnitude of the magnetic field at…
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