TS EAMCET · Maths · Circle
The number of possible common tangents that can be drawn to the circles and is
- A
- B
- C
- D
Answer & Solution
Correct Answer
(C)
Step-by-step Solution
Detailed explanation
Two circles given are x2+y2+4x-6y-3=0 & x2+y2+4x-2y+1=0 Now compare 1 with x2+y2+2gx+2hy+c=0 we get 2g=4⇒g=2 & 2h=-6 ⇒h=-3 Centre of circle is given by -g,-h ,so C1-2,3 gives the centre of first circle Similarly , C2-2,1…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Maths
- If the equation \(x^2-3 a x+a^2-2 a-\mathrm{K}=0\) has different real roots for every rational number \(a\), then K lies in the intervalTS EAMCET 2025 Hard
- Let \(z=a-\frac{i}{2} ; a \in R\). Then \(|i+z|^2-|i-z|^2\) is equal toTS EAMCET 2011 Easy
- Consider the simultaneous linear equations \(\mathrm{AX}=\mathrm{B}\) and \(\mathrm{AY}=\mathrm{Q}\). If \(\mathrm{A}\) is an invertible matrix and \(\mathrm{B}\) is the unique solution of \(\mathrm{AY}=\mathrm{Q}\), then the solution of \(\mathrm{AX}=\mathrm{B}\) isTS EAMCET 2022 Hard
- If \(\theta=\frac{\pi}{6}\), then the \(10^{\text {th }}\) term of the series \(1+(\cos \theta+i \sin \theta)^1+(\cos \theta+i \sin \theta)^2+\ldots\) isTS EAMCET 2023 Easy
- The area of the parallelogram formed by the lines \(\mathrm{L}_1 \equiv \lambda x+4 y+2=0, \mathrm{~L}_2 \equiv 3 x+4 y-3=0\), \(\mathrm{L}_3 \equiv 2 x+\mu y+6=0, \quad \mathrm{~L}_4 \equiv 2 x+y+3=0\), where \(\mathrm{L}_1\) is parallel to \(L_2\) and \(L_3\) is parallel to \(L_4\) isTS EAMCET 2024 Easy
- Find the equation to the parabola, whose axis parallel to the \(y\)-axis and which passes through the points \((0,4),(1,9)\) and \((4,5)\) isTS EAMCET 2010 Easy
More PYQs from TS EAMCET
- A diatomic gas of volume at pressure is compressed adiabatically to a volume The work done in this process is,
[Use ]TS EAMCET 2021 Easy - Decreasing order of reactivity of the following compounds in the Williamson's ether synthesis is
TS EAMCET 2022 Medium - If \(\sum_{n=1}^k \tan ^{-1}\left(\frac{1}{n^2+3 n+3}\right)=\tan ^{-1} \alpha\), then \(\alpha=\)TS EAMCET 2020 Medium
- If the focal chord drawn through the point \((1,2)\) to the parabola \(y^2=8 x\) meets this parabola in \(\left(x_1, y_1\right)\) and \(\left(x_2, y_2\right)\) then \(x_1+x_2=\)TS EAMCET 2022 Hard
- The loss of strength of a signal while propagating through a medium is known asTS EAMCET 2023 Easy
- If the rate of change of the slope of the tangent drawn to the curve \(y=x^3-2 x^2+3 x-2\) at the point \((2,4)\) is k times the rate of change of its abscissa, then \(\mathrm{k}=\)TS EAMCET 2025 Medium