TS EAMCET · Maths · Straight Lines
The area of the parallelogram formed by the lines \(\mathrm{L}_1 \equiv \lambda x+4 y+2=0, \mathrm{~L}_2 \equiv 3 x+4 y-3=0\), \(\mathrm{L}_3 \equiv 2 x+\mu y+6=0, \quad \mathrm{~L}_4 \equiv 2 x+y+3=0\), where \(\mathrm{L}_1\) is parallel to \(L_2\) and \(L_3\) is parallel to \(L_4\) is
- A \(9\)
- B \(7\)
- C \(5\)
- D \(3\)
Answer & Solution
Correct Answer
(D) \(3\)
Step-by-step Solution
Detailed explanation
\begin{aligned} & \lambda x+4 y+2=0 \text { is parallel to } 3 x+4 y-3=0 \\ & \Rightarrow \frac{-\lambda}{4}=\frac{-3}{4} \Rightarrow \lambda=3 \\ & 2 x+\mu y+6=0 \text { is parallel to } 2 x+y+3=0 \\ & \Rightarrow \frac{-2}{\mu}=-2 \Rightarrow \mu=1 \\ & A…
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