TS EAMCET · Maths · Circle
The length of the chord intercepted by the circle \(x^2+y^2+2 x+4 y-20=0\) on the line \(3 x+4 y-6=0\) is
- A \(5 \sqrt{21}\)
- B \(\frac{4}{5} \sqrt{21}\)
- C \(\frac{8}{5} \sqrt{21}\)
- D \(5 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{8}{5} \sqrt{21}\)
Step-by-step Solution
Detailed explanation
Given, Circle \(x^2+y^2+2 x+4 y-20=0\) Line \(3 x+4 y-6=0\) Put \(y=\frac{6-3 x}{4}\) from line into circle, we have \[ x^2+\left(\frac{6-3 x}{4}\right)^2+2 x+4\left(\frac{6-3 x}{4}\right)-20=0 \]…
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