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TS EAMCET · Chemistry · Coordination Compounds

Consider the complexes. (i) \(\left[\mathrm{Pd}\left(\mathrm{NH}_3\right)_2 \mathrm{ClBr}\right]\) (ii) \(\left[\mathrm{Pd}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]\) (iii) \(\left[\mathrm{Pd}(\mathrm{en}) \mathrm{Cl}_2\right]\) (iv) [Pd(en) \(\mathrm{ClBr}]\) (v) \(\left[\mathrm{Pd}(\mathrm{en})_2\right] \mathrm{Cl}_2 \quad\) (en = ethylenediamine) The total number of geometrical isomers of (A) is same as the total number of geometrical isomers of

  1. A (ii)
  2. B (iii)
  3. C (iv)
  4. D (v)
Verified Solution

Answer & Solution

Correct Answer

(A) (ii)

Step-by-step Solution

Detailed explanation

(i) \(\left[\mathrm{Pd}\left(\mathrm{NH}_3\right)_2 \mathrm{ClBr}\right]\) (ii) \(\left[\mathrm{Pd}\left(\mathrm{NH}_3\right)_2 \mathrm{Cl}_2\right]\) \(M a_2 b c\) \(M a_2 b_2\) G.I \(=2\) G.I \(=2\) cis and trans cis and trans (iii)…