TS EAMCET · Maths · Continuity and Differentiability
If \(f: R \rightarrow R\) defined as \(f(x)=\frac{x^3+2 x^2+x+2}{x^2+x-2}\) (when \(x \neq-2\) ) is continuous at \(x=-2\), then \(f(-2)\) is equal to
- A 5
- B \(\frac{-5}{3}\)
- C 2
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(B) \(\frac{-5}{3}\)
Step-by-step Solution
Detailed explanation
Given, \(f(x)=\frac{x^3+2 x^2+x+2}{x^2+x-2}\) is continuous at \(x=-2\)…
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