TS EAMCET · Maths · Probability
There are 10 coins in a box out of which 8 are normal and the remaining are with heads on both sides. A coin is chosen at random from the box and tossed 6 times. If it shows heads each time, then the probability that the selected coin has head on both sides is
- A \(\frac{16}{17}\)
- B \(\frac{32}{41}\)
- C \(\frac{8}{9}\)
- D \(\frac{12}{13}\)
Answer & Solution
Correct Answer
(A) \(\frac{16}{17}\)
Step-by-step Solution
Detailed explanation
\(P(\) both side head \()=\frac{2}{10}\) \(P(\) Fair coin \()=\frac{8}{10}\) \(\begin{aligned} & P\left(\frac{\text { Head }}{\text { Fair }}\right)=\left(\frac{1}{2}\right)^6 \\ & P\left(\frac{\text { Head }}{\text { Unfair }}\right)=1\end{aligned}\) Probability…
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