TS EAMCET · Maths · Complex Number
The least positive integral value of \(n\) such that \(\left[\frac{1+\sin \frac{2 \pi}{9}+i \cos \frac{2 \pi}{9}}{1+\sin \frac{2 \pi}{9}-i \cos \frac{2 \pi}{9}}\right]^n=1\) is
- A 9
- B 18
- C 36
- D 72
Answer & Solution
Correct Answer
(C) 36
Step-by-step Solution
Detailed explanation
\(\left[\frac{1+\sin \frac{2 \pi}{9}+i \cos \frac{2 \pi}{9}}{1+\sin \frac{2 \pi}{9}-i \cos \frac{2 \pi}{9}}\right]^n=1\)…
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