TS EAMCET · Maths · Quadratic Equation
If \(\alpha\) and \(\beta\) are two complex roots of the equation \(6 x^6-25 x^5+31 x^4-31 x^2+25 x-6=0\), then \(\alpha+\beta=\)
- A \(\frac{1}{5}\)
- B \(\frac{31}{5}\)
- C \(\frac{6}{31}\)
- D \(\frac{5}{3}\)
Answer & Solution
Correct Answer
(D) \(\frac{5}{3}\)
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