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TS EAMCET · Maths · Binomial Theorem

If the \(k^{\text {th }}\) term in the expansion of \(\left(\frac{3}{2} x^2-\frac{1}{3 x}\right)^6\) is independent of \(x\), then the numerically greatest term in the expansion of \(\left(\frac{3}{2} x^2-\frac{1}{3 x}\right)^k\) when \(x=\frac{2}{3}\), is

  1. A \(\frac{40}{81}\)
  2. B \(\left(\frac{7}{6}\right)^5\)
  3. C \(\frac{20}{27}\)
  4. D \(\left(\frac{7}{6}\right)^4\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(\frac{20}{27}\)

Step-by-step Solution

Detailed explanation

We have, \(k^{\text {th }}\) term is the expansion of \(\left(\frac{3}{2} x^2-\frac{1}{3 x}\right)^6\) is independent of \(x\)…