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TS EAMCET · Maths · Properties of Triangles

In a ΔABC,cos2B-C2(b+c)2+sin2B-C2(b-c)2=

  1. A 1/a2
  2. B 2/a2
  3. C 3/a2
  4. D 4/a2
Verified Solution

Answer & Solution

Correct Answer

(A) 1/a2

Step-by-step Solution

Detailed explanation

We have to find the value of cos2B-C2(b+c)2+sin2B-C2(b-c)2, We know that, in a triangle, a=2RsinA, b=2RsinB and c=2RsinC Substituting them, cos2B-C2(b+c)2+sin2B-C2(b-c)2=cos2B-C22R· sin B+2R· sin C2+sin2B-C22R· sin B-2R&…