TS EAMCET · Maths · Three Dimensional Geometry
The foot of the perpendicular drawn from the point \((-2,-1,3)\) to a plane \(\pi\) is \((1,0,-2)\). If \(a, b, c\) are the intercepts made by the plane \(\pi\) on \(X, Y, Z\)-axes respectively, then \(3 a+b+5 c=\)
- A \(39\)
- B \(26\)
- C \(13\)
- D \(0\)
Answer & Solution
Correct Answer
(C) \(13\)
Step-by-step Solution
Detailed explanation
Equation of plane is \(a(x-1)+b y+c(z+2)=0\) \(D R\) 's of line \(\perp \pi\) are \( \lt -3,-1,5\gt\) \(D R\) 's of line \(\perp \pi\) are \( \lt a, b, c\gt\) \(\begin{aligned} & \frac{a}{-3}=\frac{b}{-1}=\frac{c}{5}=K \\ & a=-3 K ; b=-K ; c=5 K \end{aligned}\) Equation of plane…
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