TS EAMCET · Maths · Complex Number
If \(a=|\bar{a}| ; b=|\bar{b}|\) then \(\left(\frac{\bar{a}}{a^2}-\frac{\bar{b}}{b^2}\right)^2=\)
- A \(\left(\frac{\bar{a}-\bar{b}}{a^2 b^2}\right)^2\)
- B \(\left(\frac{\bar{a}-\bar{b}}{a b}\right)^2\)
- C \(\left(\frac{b \bar{a}-a \bar{b}}{a b}\right)^2\)
- D \(\left(\frac{a \bar{a}-b \bar{b}}{a^2 b^2}\right)^2\)
Answer & Solution
Correct Answer
(B) \(\left(\frac{\bar{a}-\bar{b}}{a b}\right)^2\)
Step-by-step Solution
Detailed explanation
\(\left(\frac{\bar{a}}{a^2}-\frac{\bar{b}}{b^2}\right)^2 = \frac{\bar{a} \cdot \bar{a}}{a^4} - 2\frac{\bar{a} \cdot \bar{b}}{a^2 b^2} + \frac{\bar{b} \cdot \bar{b}}{b^4}\) \(= \frac{a^2}{a^4} - 2\frac{\bar{a} \cdot \bar{b}}{a^2 b^2} + \frac{b^2}{b^4}\)…
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