TS EAMCET · Maths · Circle
The equations of the tangents to the circle \(x^2+y^2=4\) drawn from the point \((4,0)\) are
- A \(\sqrt{3} y= \pm(x-4)\)
- B \(\sqrt{3} y= \pm2(x-4)\)
- C \(\sqrt{3} x= \pm(y-4)\)
- D \(\sqrt{3} x= \pm2(y-4)\)
Answer & Solution
Correct Answer
(A) \(\sqrt{3} y= \pm(x-4)\)
Step-by-step Solution
Detailed explanation
Equation of pair of tangents, \(S S_1=T^2\)…
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