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TS EAMCET · Maths · Three Dimensional Geometry

In \(\triangle A B C\) the mid points of the sides \(A B, B C\) and \(C A\) are respectively \((l, 0,0),(0, m, 0)\) and \((0,0, n)\). Then, \(\frac{A B^2+B C^2+C A^2}{l^2+m^2+n^2}\) is equal to

  1. A \(2\)
  2. B \(4\)
  3. C \(8\)
  4. D \(16\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(8\)

Step-by-step Solution

Detailed explanation

From the figure, \( \begin{gathered} x_1+x_2=2 l, y_1+y_2=0, z_1+z_2=0, \\ x_2+x_3=0, y_2+y_3=2 m, z_2+z_3=0 \\ \text { and } \quad x_1+x_3=0, y_1+y_3=0, z_1+z_3=2 n \end{gathered} \) On solving, we get…